Optimal. Leaf size=125 \[ \frac {1}{32 a^2 \left (1-a^2 x^2\right )^2}+\frac {3}{32 a^2 \left (1-a^2 x^2\right )}-\frac {x \tanh ^{-1}(a x)}{8 a \left (1-a^2 x^2\right )^2}-\frac {3 x \tanh ^{-1}(a x)}{16 a \left (1-a^2 x^2\right )}-\frac {3 \tanh ^{-1}(a x)^2}{32 a^2}+\frac {\tanh ^{-1}(a x)^2}{4 a^2 \left (1-a^2 x^2\right )^2} \]
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Rubi [A]
time = 0.07, antiderivative size = 125, normalized size of antiderivative = 1.00, number of steps
used = 4, number of rules used = 4, integrand size = 20, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {6141, 6107,
6103, 267} \begin {gather*} \frac {3}{32 a^2 \left (1-a^2 x^2\right )}+\frac {1}{32 a^2 \left (1-a^2 x^2\right )^2}+\frac {\tanh ^{-1}(a x)^2}{4 a^2 \left (1-a^2 x^2\right )^2}-\frac {3 x \tanh ^{-1}(a x)}{16 a \left (1-a^2 x^2\right )}-\frac {x \tanh ^{-1}(a x)}{8 a \left (1-a^2 x^2\right )^2}-\frac {3 \tanh ^{-1}(a x)^2}{32 a^2} \end {gather*}
Antiderivative was successfully verified.
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Rule 267
Rule 6103
Rule 6107
Rule 6141
Rubi steps
\begin {align*} \int \frac {x \tanh ^{-1}(a x)^2}{\left (1-a^2 x^2\right )^3} \, dx &=\frac {\tanh ^{-1}(a x)^2}{4 a^2 \left (1-a^2 x^2\right )^2}-\frac {\int \frac {\tanh ^{-1}(a x)}{\left (1-a^2 x^2\right )^3} \, dx}{2 a}\\ &=\frac {1}{32 a^2 \left (1-a^2 x^2\right )^2}-\frac {x \tanh ^{-1}(a x)}{8 a \left (1-a^2 x^2\right )^2}+\frac {\tanh ^{-1}(a x)^2}{4 a^2 \left (1-a^2 x^2\right )^2}-\frac {3 \int \frac {\tanh ^{-1}(a x)}{\left (1-a^2 x^2\right )^2} \, dx}{8 a}\\ &=\frac {1}{32 a^2 \left (1-a^2 x^2\right )^2}-\frac {x \tanh ^{-1}(a x)}{8 a \left (1-a^2 x^2\right )^2}-\frac {3 x \tanh ^{-1}(a x)}{16 a \left (1-a^2 x^2\right )}-\frac {3 \tanh ^{-1}(a x)^2}{32 a^2}+\frac {\tanh ^{-1}(a x)^2}{4 a^2 \left (1-a^2 x^2\right )^2}+\frac {3}{16} \int \frac {x}{\left (1-a^2 x^2\right )^2} \, dx\\ &=\frac {1}{32 a^2 \left (1-a^2 x^2\right )^2}+\frac {3}{32 a^2 \left (1-a^2 x^2\right )}-\frac {x \tanh ^{-1}(a x)}{8 a \left (1-a^2 x^2\right )^2}-\frac {3 x \tanh ^{-1}(a x)}{16 a \left (1-a^2 x^2\right )}-\frac {3 \tanh ^{-1}(a x)^2}{32 a^2}+\frac {\tanh ^{-1}(a x)^2}{4 a^2 \left (1-a^2 x^2\right )^2}\\ \end {align*}
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Mathematica [A]
time = 0.03, size = 71, normalized size = 0.57 \begin {gather*} \frac {4-3 a^2 x^2+2 a x \left (-5+3 a^2 x^2\right ) \tanh ^{-1}(a x)+\left (5+6 a^2 x^2-3 a^4 x^4\right ) \tanh ^{-1}(a x)^2}{32 a^2 \left (-1+a^2 x^2\right )^2} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.78, size = 197, normalized size = 1.58
method | result | size |
derivativedivides | \(\frac {\frac {\arctanh \left (a x \right )^{2}}{4 \left (a^{2} x^{2}-1\right )^{2}}+\frac {\arctanh \left (a x \right )}{32 \left (a x +1\right )^{2}}+\frac {3 \arctanh \left (a x \right )}{32 \left (a x +1\right )}-\frac {3 \arctanh \left (a x \right ) \ln \left (a x +1\right )}{32}-\frac {\arctanh \left (a x \right )}{32 \left (a x -1\right )^{2}}+\frac {3 \arctanh \left (a x \right )}{32 \left (a x -1\right )}+\frac {3 \arctanh \left (a x \right ) \ln \left (a x -1\right )}{32}-\frac {3 \ln \left (a x -1\right ) \ln \left (\frac {a x}{2}+\frac {1}{2}\right )}{64}+\frac {3 \ln \left (a x -1\right )^{2}}{128}-\frac {3 \left (\ln \left (a x +1\right )-\ln \left (\frac {a x}{2}+\frac {1}{2}\right )\right ) \ln \left (-\frac {a x}{2}+\frac {1}{2}\right )}{64}+\frac {3 \ln \left (a x +1\right )^{2}}{128}+\frac {1}{128 \left (a x -1\right )^{2}}-\frac {7}{128 \left (a x -1\right )}+\frac {1}{128 \left (a x +1\right )^{2}}+\frac {7}{128 \left (a x +1\right )}}{a^{2}}\) | \(197\) |
default | \(\frac {\frac {\arctanh \left (a x \right )^{2}}{4 \left (a^{2} x^{2}-1\right )^{2}}+\frac {\arctanh \left (a x \right )}{32 \left (a x +1\right )^{2}}+\frac {3 \arctanh \left (a x \right )}{32 \left (a x +1\right )}-\frac {3 \arctanh \left (a x \right ) \ln \left (a x +1\right )}{32}-\frac {\arctanh \left (a x \right )}{32 \left (a x -1\right )^{2}}+\frac {3 \arctanh \left (a x \right )}{32 \left (a x -1\right )}+\frac {3 \arctanh \left (a x \right ) \ln \left (a x -1\right )}{32}-\frac {3 \ln \left (a x -1\right ) \ln \left (\frac {a x}{2}+\frac {1}{2}\right )}{64}+\frac {3 \ln \left (a x -1\right )^{2}}{128}-\frac {3 \left (\ln \left (a x +1\right )-\ln \left (\frac {a x}{2}+\frac {1}{2}\right )\right ) \ln \left (-\frac {a x}{2}+\frac {1}{2}\right )}{64}+\frac {3 \ln \left (a x +1\right )^{2}}{128}+\frac {1}{128 \left (a x -1\right )^{2}}-\frac {7}{128 \left (a x -1\right )}+\frac {1}{128 \left (a x +1\right )^{2}}+\frac {7}{128 \left (a x +1\right )}}{a^{2}}\) | \(197\) |
risch | \(-\frac {\left (3 a^{4} x^{4}-6 a^{2} x^{2}-5\right ) \ln \left (a x +1\right )^{2}}{128 a^{2} \left (a x +1\right ) \left (a x -1\right ) \left (a^{2} x^{2}-1\right )}+\frac {\left (3 x^{4} \ln \left (-a x +1\right ) a^{4}+6 a^{3} x^{3}-6 x^{2} \ln \left (-a x +1\right ) a^{2}-10 a x -5 \ln \left (-a x +1\right )\right ) \ln \left (a x +1\right )}{64 a^{2} \left (a x +1\right ) \left (a x -1\right ) \left (a^{2} x^{2}-1\right )}-\frac {3 a^{4} x^{4} \ln \left (-a x +1\right )^{2}+12 a^{3} x^{3} \ln \left (-a x +1\right )-6 a^{2} x^{2} \ln \left (-a x +1\right )^{2}+12 a^{2} x^{2}-20 a x \ln \left (-a x +1\right )-5 \ln \left (-a x +1\right )^{2}-16}{128 a^{2} \left (a x +1\right ) \left (a x -1\right ) \left (a^{2} x^{2}-1\right )}\) | \(257\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.26, size = 206, normalized size = 1.65 \begin {gather*} \frac {{\left (\frac {2 \, {\left (3 \, a^{2} x^{3} - 5 \, x\right )}}{a^{4} x^{4} - 2 \, a^{2} x^{2} + 1} - \frac {3 \, \log \left (a x + 1\right )}{a} + \frac {3 \, \log \left (a x - 1\right )}{a}\right )} \operatorname {artanh}\left (a x\right )}{32 \, a} - \frac {12 \, a^{2} x^{2} - 3 \, {\left (a^{4} x^{4} - 2 \, a^{2} x^{2} + 1\right )} \log \left (a x + 1\right )^{2} + 6 \, {\left (a^{4} x^{4} - 2 \, a^{2} x^{2} + 1\right )} \log \left (a x + 1\right ) \log \left (a x - 1\right ) - 3 \, {\left (a^{4} x^{4} - 2 \, a^{2} x^{2} + 1\right )} \log \left (a x - 1\right )^{2} - 16}{128 \, {\left (a^{6} x^{4} - 2 \, a^{4} x^{2} + a^{2}\right )}} + \frac {\operatorname {artanh}\left (a x\right )^{2}}{4 \, {\left (a^{2} x^{2} - 1\right )}^{2} a^{2}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.36, size = 99, normalized size = 0.79 \begin {gather*} -\frac {12 \, a^{2} x^{2} + {\left (3 \, a^{4} x^{4} - 6 \, a^{2} x^{2} - 5\right )} \log \left (-\frac {a x + 1}{a x - 1}\right )^{2} - 4 \, {\left (3 \, a^{3} x^{3} - 5 \, a x\right )} \log \left (-\frac {a x + 1}{a x - 1}\right ) - 16}{128 \, {\left (a^{6} x^{4} - 2 \, a^{4} x^{2} + a^{2}\right )}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} - \int \frac {x \operatorname {atanh}^{2}{\left (a x \right )}}{a^{6} x^{6} - 3 a^{4} x^{4} + 3 a^{2} x^{2} - 1}\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] Leaf count of result is larger than twice the leaf count of optimal. 251 vs.
\(2 (108) = 216\).
time = 0.41, size = 251, normalized size = 2.01 \begin {gather*} -\frac {1}{512} \, {\left (2 \, {\left (\frac {{\left (a x - 1\right )}^{2} {\left (\frac {4 \, {\left (a x + 1\right )}}{a x - 1} - 1\right )}}{{\left (a x + 1\right )}^{2} a^{3}} - \frac {{\left (a x + 1\right )}^{2}}{{\left (a x - 1\right )}^{2} a^{3}} + \frac {4 \, {\left (a x + 1\right )}}{{\left (a x - 1\right )} a^{3}}\right )} \log \left (-\frac {a x + 1}{a x - 1}\right )^{2} + 2 \, {\left (\frac {{\left (a x - 1\right )}^{2} {\left (\frac {8 \, {\left (a x + 1\right )}}{a x - 1} - 1\right )}}{{\left (a x + 1\right )}^{2} a^{3}} + \frac {{\left (a x + 1\right )}^{2}}{{\left (a x - 1\right )}^{2} a^{3}} - \frac {8 \, {\left (a x + 1\right )}}{{\left (a x - 1\right )} a^{3}}\right )} \log \left (-\frac {a x + 1}{a x - 1}\right ) + \frac {{\left (a x - 1\right )}^{2} {\left (\frac {16 \, {\left (a x + 1\right )}}{a x - 1} - 1\right )}}{{\left (a x + 1\right )}^{2} a^{3}} - \frac {{\left (a x + 1\right )}^{2}}{{\left (a x - 1\right )}^{2} a^{3}} + \frac {16 \, {\left (a x + 1\right )}}{{\left (a x - 1\right )} a^{3}}\right )} a \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [B]
time = 1.48, size = 319, normalized size = 2.55 \begin {gather*} {\ln \left (a\,x+1\right )}^2\,\left (\frac {1}{16\,a^3\,\left (\frac {1}{a}-2\,a\,x^2+a^3\,x^4\right )}-\frac {3}{128\,a^2}\right )-{\ln \left (1-a\,x\right )}^2\,\left (\frac {3}{128\,a^2}-\frac {1}{4\,a^2\,\left (4\,a^4\,x^4-8\,a^2\,x^2+4\right )}\right )-\ln \left (1-a\,x\right )\,\left (\frac {\frac {1}{4\,a}-\frac {5\,x}{8}+\frac {3\,a^2\,x^3}{8}}{8\,a^5\,x^4-16\,a^3\,x^2+8\,a}-\frac {\frac {5\,x}{8}+\frac {1}{4\,a}-\frac {3\,a^2\,x^3}{8}}{8\,a^5\,x^4-16\,a^3\,x^2+8\,a}+\ln \left (a\,x+1\right )\,\left (\frac {1}{4\,a^2\,\left (2\,a^4\,x^4-4\,a^2\,x^2+2\right )}-\frac {3\,\left (a^4\,x^4-2\,a^2\,x^2+1\right )}{32\,a^2\,\left (2\,a^4\,x^4-4\,a^2\,x^2+2\right )}\right )\right )+\frac {\frac {2}{a^2}-\frac {3\,x^2}{2}}{16\,a^4\,x^4-32\,a^2\,x^2+16}-\frac {\ln \left (a\,x+1\right )\,\left (\frac {5\,x}{32\,a^2}-\frac {3\,x^3}{32}\right )}{\frac {1}{a}-2\,a\,x^2+a^3\,x^4} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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